What is (x+1)^4-(x-1)^4 ?

The solution to (x+1)^4-(x-1)^4 is 8x^3+8x

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simplify (x+1)^4-(x-1)^4

simplify

(x + 1)^{4} - (x - 1)^{4}

8 x^{3} + 8 x

Solution steps

(x + 1)^{4} - (x - 1)^{4}

(x + 1)^{4} : x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1

= x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1 - (x - 1)^{4}

(x - 1)^{4} : x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

= x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1 - (x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1)

- (x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1) : - x^{4} + 4 x^{3} - 6 x^{2} + 4 x - 1

= x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1 - x^{4} + 4 x^{3} - 6 x^{2} + 4 x - 1

Simplify

x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1 - x^{4} + 4 x^{3} - 6 x^{2} + 4 x - 1 : 8 x^{3} + 8 x

= 8 x^{3} + 8 x

3 f^{3} g^{0}

- 3 \frac{y}{( y - z )} + \frac{z}{( y ) ^{2}}

(\frac{( x ^{4} )}{( y ^{2} )})^{\frac{1}{2}}

(x + 2) \cdot (x^{2} - 2 x + 3)

1 z^{0} - 1060 - 22