What are the solutions to the equation x^2=10-4x ?

The solutions to the equation x^2=10-4x are x=-2+sqrt(14),x=-2-sqrt(14)

Find the zeros of x^2=10-4x

The zeros of x^2=10-4x are x=-2+sqrt(14),x=-2-sqrt(14)

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x^{2} = 10 - 4 x

x = - 2 + 14, x = - 2 - 14

Decimal Notation

x = 1.74165 \dots, x = - 5.74165 \dots

Solution steps

x^{2} = 10 - 4 x

Move

4 x

to the left side

x^{2} + 4 x = 10

Move

10

to the left side

x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 10) = 214

x_{1, 2} = \frac{- 4 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 14}{2 \cdot 1}

x = \frac{- 4 + 2 14}{2 \cdot 1} : - 2 + 14

x = \frac{- 4 - 2 14}{2 \cdot 1} : - 2 - 14

The solutions to the quadratic equation are:

x = - 2 + 14, x = - 2 - 14

x^{2} = 2 x + 15

\frac{3}{2} - 2 x \geq \frac{1}{2}

- 3 - 27

3 = \frac{x}{3.3}

3 x^{2} + 32 x + 20

What are the solutions to the equation x^2=10-4x ?
The solutions to the equation x^2=10-4x are x=-2+sqrt(14),x=-2-sqrt(14)
Find the zeros of x^2=10-4x
The zeros of x^2=10-4x are x=-2+sqrt(14),x=-2-sqrt(14)