What is expand (4x^2-1)(4x^2+1) ?

The solution to expand (4x^2-1)(4x^2+1) is 16x^4-1

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expand (4x^2-1)(4x^2+1)

expand

(4 x^{2} - 1) (4 x^{2} + 1)

16 x^{4} - 1

Solution steps

(4 x^{2} - 1) (4 x^{2} + 1)

Apply Difference of Two Squares

(4 x^{2} - 1) (4 x^{2} + 1) : 16 x^{4} - 1

= 16 x^{4} - 1

\frac{7 p ^{6}}{7 c ^{6}}

\frac{2 x ^{4} - 3 x ^{4} + 3 x ^{2}}{x ^{6}}

\frac{( a ^{3} - 2 a ^{2} \cdot b )}{( 2 a ^{3} \cdot b ^{2} - a ^{4} \cdot b )}

\frac{1}{2} + \frac{1}{2} + 4 + 6 + \frac{1}{2} + 4 + 6 + 8 + \frac{1}{2} + 4 + 6 + 8 + 2 n

5 \frac{x}{9} + 7 \frac{x ^{2}}{3}

What is expand (4x^2-1)(4x^2+1) ?
The solution to expand (4x^2-1)(4x^2+1) is 16x^4-1