What is (t+2)(t^2-2t+4)-(t-2)(t^2+2t+4) ?

The solution to (t+2)(t^2-2t+4)-(t-2)(t^2+2t+4) is 16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (t+2)(t^2-2t+4)-(t-2)(t^2+2t+4)

simplify

(t + 2) (t^{2} - 2 t + 4) - (t - 2) (t^{2} + 2 t + 4)

16

Solution steps

(t + 2) (t^{2} - 2 t + 4) - (t - 2) (t^{2} + 2 t + 4)

Expand

(t + 2) (t^{2} - 2 t + 4) : t^{3} + 8

= t^{3} + 8 - (t - 2) (t^{2} + 2 t + 4)

Expand

- (t - 2) (t^{2} + 2 t + 4) : - t^{3} + 8

= t^{3} + 8 - t^{3} + 8

Group like terms

= t^{3} - t^{3} + 8 + 8

Add similar elements:

t^{3} - t^{3} = 0

= 8 + 8

Add the numbers:

8 + 8 = 16

= 16

\frac{\frac{c ^{3}}{515}}{\frac{42}{7}}

\frac{cos ^{4} ( x ) - sin ^{4} ( x )}{cos ^{2} ( x ) - sin ^{2} ( x )}

det (2 a^{- 1} b)

(2 x - 2)^{- 3}

(\frac{( 3 + 2 ) a}{3})^{2}

What is (t+2)(t^2-2t+4)-(t-2)(t^2+2t+4) ?
The solution to (t+2)(t^2-2t+4)-(t-2)(t^2+2t+4) is 16