What is d[(10)/x-4x+3x^0] ?

The solution to d[(10)/x-4x+3x^0] is d((10)/x-4x+3)

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simplify d[(10)/x-4x+3x^0]

simplify

d [\frac{10}{x} - 4 x + 3 x^{0}]

d (\frac{10}{x} - 4 x + 3)

Solution steps

d (\frac{10}{x} - 4 x + 3 x^{0})

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= d (\frac{10}{x} - 4 x + 3 \cdot 1)

Multiply the numbers:

3 \cdot 1 = 3

= d (\frac{10}{x} - 4 x + 3)

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