What is 8^x-1/(2^y)+2 ?

The solution to 8^x-1/(2^y)+2 is (2^{3x+y}-1+2^{1+y})/(2^y)

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simplify 8^x-1/(2^y)+2

simplify

8^{x} - \frac{1}{2 ^{y}} + 2

\frac{2 ^{3 x + y} - 1 + 2 ^{1 + y}}{2 ^{y}}

Solution steps

8^{x} - \frac{1}{2 ^{y}} + 2

Convert

8^{x}

to fraction

: \frac{2 ^{3 x + y}}{2 ^{y}}

Convert

2

to fraction

: \frac{2 ^{1 + y}}{2 ^{y}}

= \frac{2 ^{3 x + y}}{2 ^{y}} - \frac{1}{2 ^{y}} + \frac{2 ^{1 + y}}{2 ^{y}}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 ^{3 x + y} - 1 + 2 ^{1 + y}}{2 ^{y}}

6 x - 2 y

\frac{( a ^{10} + b ^{10} )}{( a ^{- 1} 0 + b ^{- 1} 0 )}

\frac{( z - 3 i )}{( 5 i )}

e^{2} t + e^{- 2} t

sin^{2} (x) - cos^{2} (x) + cos (x)

What is 8^x-1/(2^y)+2 ?
The solution to 8^x-1/(2^y)+2 is (2^{3x+y}-1+2^{1+y})/(2^y)