What is (1.86)/(0.3)-1/6 \times (19.3-14/5)+0.3\times 6.8 ?

The solution to (1.86)/(0.3)-1/6 \times (19.3-14/5)+0.3\times 6.8 is 549/100

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simplify (1.86)/(0.3)-1/6 \times (19.3-14/5)+0.3\times 6.8

simplify

\frac{1.86}{0.3} - \frac{1}{6} \cdot (19.3 - \frac{14}{5}) + 0.3 \cdot 6.8

\frac{549}{100}

Decimal Notation

5.49

Solution steps

\frac{1.86}{0.3} - \frac{1}{6} (19.3 - \frac{14}{5}) + 0.3 \cdot 6.8

0.3 = \frac{3}{10}

= \frac{1.86}{0.3} - \frac{1}{6} (19.3 - \frac{14}{5}) + \frac{3}{10} \cdot 6.8

6.8 = \frac{34}{5}

= \frac{1.86}{0.3} - \frac{1}{6} (19.3 - \frac{14}{5}) + \frac{3}{10} \cdot \frac{34}{5}

\frac{1.86}{0.3} = \frac{186}{30}

= \frac{186}{30} - \frac{1}{6} (19.3 - \frac{14}{5}) + \frac{3}{10} \cdot \frac{34}{5}

\frac{1}{6} (19.3 - \frac{14}{5}) = \frac{11}{4}

\frac{3}{10} \cdot \frac{34}{5} = \frac{51}{25}

= \frac{186}{30} - \frac{11}{4} + \frac{51}{25}

\frac{186}{30} - \frac{11}{4} + \frac{51}{25} = \frac{549}{100}

= \frac{549}{100}

(5 x \cdot + 7 y) (5 x \cdot + 7 y)

(3 y + 4 y)^{3}

1 (5 x - 2) + (- 2) (9 x)

(\frac{1 + 1}{n})^{n}

(a^{2} + a)^{31}

What is (1.86)/(0.3)-1/6 \times (19.3-14/5)+0.3\times 6.8 ?
The solution to (1.86)/(0.3)-1/6 \times (19.3-14/5)+0.3\times 6.8 is 549/100