What is factor t^3+t^2-4t-64 ?

The solution to factor t^3+t^2-4t-64 is (t-4)(t^2+5t+16)

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factor t^3+t^2-4t-64

factor

t^{3} + t^{2} - 4 t - 64

(t - 4) (t^{2} + 5 t + 16)

Solution steps

t^{3} + t^{2} - 4 t - 64

Use the rational root theorem

= (t - 4) \frac{t ^{3} + t ^{2} - 4 t - 64}{t - 4}

\frac{t ^{3} + t ^{2} - 4 t - 64}{t - 4} = t^{2} + 5 t + 16

= (t - 4) (t^{2} + 5 t + 16)

5 (x^{2} + 3) + 3 x^{2} - 9

2^{l o g_{2} (\frac{1}{4})} a

\frac{( 3 x ^{2} - 4 x \cdot y ^{2} + y )}{( 9 x ^{2} - y ^{2} )}

\frac{( 2 x )}{( 4 x )}

\frac{( - 2 a ^{2} ) ^{3}}{b ^{3}}

What is factor t^3+t^2-4t-64 ?
The solution to factor t^3+t^2-4t-64 is (t-4)(t^2+5t+16)