What is ((a+x)^2-9)/((a+x)+3) ?

The solution to ((a+x)^2-9)/((a+x)+3) is a+x-3

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simplify ((a+x)^2-9)/((a+x)+3)

simplify

\frac{( a + x ) ^{2} - 9}{( a + x ) + 3}

a + x - 3

Solution steps

\frac{( a + x ) ^{2} - 9}{( a + x ) + 3}

Apply rule:

(a) = a

(a + x) = a + x

= \frac{( a + x ) ^{2} - 9}{a + x + 3}

Factor

(a + x)^{2} - 9 : (a + x + 3) (a + x - 3)

= \frac{( a + x + 3 ) ( a + x - 3 )}{a + x + 3}

Cancel the common factor:

a + x + 3

= a + x - 3

\frac{( ( 243 ) ^{\frac{n}{5}} \cdot 3 ^{2 n + 1} )}{( 9 ^{n} \cdot 3 ^{n - 1} )}

(\frac{1}{2 a ^{- 2}})^{- 3}

25 m^{8} - 9 n^{6}

x^{2} + y^{2} + 4 x - 4 x - 4 x - \frac{1}{0}

\frac{2 ^{5 x}}{7 ^{x}}