What is (81x^{-2}4y^{16}z^{52})^0+7 ?

The solution to (81x^{-2}4y^{16}z^{52})^0+7 is 8

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simplify (81x^{-2}4y^{16}z^{52})^0+7

simplify

(81 x^{- 2} 4 y^{16} z^{52})^{0} + 7

8

Solution steps

(81 x^{- 2} \cdot 4 y^{16} z^{52})^{0} + 7

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(81 x^{- 2} \cdot 4 y^{16} z^{52})^{0} = 1

= 1 + 7

Add the numbers:

1 + 7 = 8

= 8

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2 (sin (x) - cos (x)) - (sin (2 x) - cos (2 x))

What is (81x^{-2}4y^{16}z^{52})^0+7 ?
The solution to (81x^{-2}4y^{16}z^{52})^0+7 is 8