What is ((2x^5y^5)/(4x^2))^3 ?

The solution to ((2x^5y^5)/(4x^2))^3 is (x^9y^{15})/8

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simplify ((2x^5y^5)/(4x^2))^3

simplify

(\frac{2 x ^{5} y ^{5}}{4 x ^{2}})^{3}

\frac{x ^{9} y ^{15}}{8}

Solution steps

(\frac{2 x ^{5} y ^{5}}{4 x ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ^{5} y ^{5} ) ^{3}}{( 4 x ^{2} ) ^{3}}

Simplify

(2 x^{5} y^{5})^{3} : 8 x^{15} y^{15}

= \frac{8 x ^{15} y ^{15}}{( 4 x ^{2} ) ^{3}}

Simplify

(4 x^{2})^{3} : 64 x^{6}

= \frac{8 x ^{15} y ^{15}}{64 x ^{6}}

Cancel the common factor:

8

= \frac{x ^{15} y ^{15}}{8 x ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{15}}{x ^{6}} = x^{15 - 6}

= \frac{y ^{15} x ^{15 - 6}}{8}

Subtract the numbers:

15 - 6 = 9

= \frac{x ^{9} y ^{15}}{8}

m^{3} + 8

2 x^{2} + x^{3}

(\frac{( x ^{2} \cdot y ^{2} )}{( a ^{2} \cdot b ^{2} )})^{0}

25 x^{2} y^{4} - 49

\frac{1}{2} \cdot (\frac{1}{s} + \frac{s}{( s ^{2} + 36 )})

What is ((2x^5y^5)/(4x^2))^3 ?
The solution to ((2x^5y^5)/(4x^2))^3 is (x^9y^{15})/8