What is ((2^{n+1}*2^{n-1}))/((2^{n+2)*2^{n-2})} ?

The solution to ((2^{n+1}*2^{n-1}))/((2^{n+2)*2^{n-2})} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2^{n+1}2^{n-1}))/((2^{n+2)2^{n-2})}

simplify

\frac{( 2 ^{n + 1} \cdot 2 ^{n - 1} )}{( 2 ^{n + 2} \cdot 2 ^{n - 2} )}

1

Solution steps

\frac{2 ^{n + 1} \cdot 2 ^{n - 1}}{2 ^{n + 2} \cdot 2 ^{n - 2}}

Simplify

2^{n + 1} \cdot 2^{n - 1} : 2^{2 n}

= \frac{2 ^{2 n}}{2 ^{n + 2} \cdot 2 ^{n - 2}}

Simplify

\frac{2 ^{2 n}}{2 ^{n + 2}} : 2^{n - 2}

= \frac{2 ^{n - 2}}{2 ^{n - 2}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

1^{a + b}

f (x) 2 x^{3} - 26 x + 24

- 2 x^{0} y^{2} z^{- 2}

- 3 x y (x - 1) + 5 x (x - 1)

3 a - 5 b - a + 2 b

What is ((2^{n+1}*2^{n-1}))/((2^{n+2)*2^{n-2})} ?
The solution to ((2^{n+1}*2^{n-1}))/((2^{n+2)*2^{n-2})} is 1