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What are the solutions to the equation (4/5)^2+y^2=1 ?
The solutions to the equation (4/5)^2+y^2=1 are y= 3/5 ,y=-3/5Find the zeros of (4/5)^2+y^2=1
The zeros of (4/5)^2+y^2=1 are y= 3/5 ,y=-3/5