What is expand (4a^6-b^7)^3 ?

The solution to expand (4a^6-b^7)^3 is 64a^{18}-48a^{12}b^7+12a^6b^{14}-b^{21}

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expand (4a^6-b^7)^3

expand

(4 a^{6} - b^{7})^{3}

64 a^{18} - 48 a^{12} b^{7} + 12 a^{6} b^{14} - b^{21}

Solution steps

(4 a^{6} - b^{7})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(4 a^{6} - b^{7})^{3} = (4 a^{6})^{3} - 3 (4 a^{6})^{2} b^{7} + 3 \cdot 4 a^{6} (b^{7})^{2} - (b^{7})^{3}

= (4 a^{6})^{3} - 3 (4 a^{6})^{2} b^{7} + 3 \cdot 4 a^{6} (b^{7})^{2} - (b^{7})^{3}

Simplify

(4 a^{6})^{3} - 3 (4 a^{6})^{2} b^{7} + 3 \cdot 4 a^{6} (b^{7})^{2} - (b^{7})^{3} : 64 a^{18} - 48 a^{12} b^{7} + 12 a^{6} b^{14} - b^{21}

= 64 a^{18} - 48 a^{12} b^{7} + 12 a^{6} b^{14} - b^{21}

25 x^{2} - 10 x + 1 - 36 y^{2}

\frac{6 r ^{2}}{9 r ^{- 1}}

x^{4} + 4 x^{2} y^{2} + 4 y^{4} - 16

(3 x y + 4)^{3}

(a - 7) (a + 7)

What is expand (4a^6-b^7)^3 ?
The solution to expand (4a^6-b^7)^3 is 64a^{18}-48a^{12}b^7+12a^6b^{14}-b^{21}