What is (tan^5(x))/(sin^2(x)) ?

The solution to (tan^5(x))/(sin^2(x)) is tan^5(x)csc^2(x)

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simplify (tan^5(x))/(sin^2(x))

simplify

\frac{tan ^{5} ( x )}{sin ^{2} ( x )}

tan^{5} (x) csc^{2} (x)

Solution steps

\frac{tan ^{5} ( x )}{sin ^{2} ( x )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= tan^{5} (x) csc^{2} (x)

25 - b^{2}

\frac{( - 8 x ^{2} + 4 x y + 6 x )}{2}

((\frac{1}{n + i})^{i})^{n}

(1) \cdot 27 a^{3} - 64 b^{3}

tan^{\frac{- 1}{2}} (a) + tan^{\frac{- 1}{2}} (b)

What is (tan^5(x))/(sin^2(x)) ?
The solution to (tan^5(x))/(sin^2(x)) is tan^5(x)csc^2(x)