What is ((2x-y)/5)((2x+y)/5) ?

The solution to ((2x-y)/5)((2x+y)/5) is ((2x-y)(2x+y))/(25)

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simplify ((2x-y)/5)((2x+y)/5)

simplify

(\frac{2 x - y}{5}) (\frac{2 x + y}{5})

\frac{( 2 x - y ) ( 2 x + y )}{25}

Solution steps

(\frac{2 x - y}{5}) (\frac{2 x + y}{5})

Simplify

(\frac{2 x - y}{5}) (\frac{2 x + y}{5}) : \frac{2 x - y}{5} \cdot \frac{2 x + y}{5}

= \frac{2 x - y}{5} \cdot \frac{2 x + y}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 2 x - y ) ( 2 x + y )}{5 \cdot 5}

Multiply the numbers:

5 \cdot 5 = 25

= \frac{( 2 x - y ) ( 2 x + y )}{25}

(5 x + 4)^{3}

- 80 x + 5 x^{5}

(a^{3} - b^{3})^{3}

121 x^{2} - 44 x y + 4 x^{2}

7 x - 7 - 8 x

What is ((2x-y)/5)((2x+y)/5) ?
The solution to ((2x-y)/5)((2x+y)/5) is ((2x-y)(2x+y))/(25)