What is 0t+2(5+x)-(8+x)*(z+x)^2 ?

The solution to 0t+2(5+x)-(8+x)*(z+x)^2 is 10+2x-8z^2-xz^2-16xz-2x^2z-8x^2-x^3

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simplify 0t+2(5+x)-(8+x)*(z+x)^2

simplify

0 t + 2 (5 + x) - (8 + x) \cdot (z + x)^{2}

10 + 2 x - 8 z^{2} - x z^{2} - 16 x z - 2 x^{2} z - 8 x^{2} - x^{3}

Solution steps

0 \cdot t + 2 (5 + x) - (8 + x) (z + x)^{2}

Apply rule:

a \cdot 0 = 0

0 \cdot t = 0

= 0 + 2 (5 + x) - (8 + x) (z + x)^{2}

= 0 + 2 (5 + x) - (z + x)^{2} (8 + x)

Expand

2 (5 + x) : 10 + 2 x

= 0 + 10 + 2 x - (z + x)^{2} (8 + x)

Expand

- (z + x)^{2} (8 + x) : - 8 z^{2} - x z^{2} - 16 x z - 2 x^{2} z - 8 x^{2} - x^{3}

= 0 + 10 + 2 x - 8 z^{2} - x z^{2} - 16 x z - 2 x^{2} z - 8 x^{2} - x^{3}

Add the numbers:

0 + 10 = 10

= 10 + 2 x - 8 z^{2} - x z^{2} - 16 x z - 2 x^{2} z - 8 x^{2} - x^{3}

(2 x + 1)^{2} + (3 x - 1)^{2} + 2 (2 x + 1) (3 x - 1)

(\frac{a}{4} - \frac{b}{2} + 1)^{2}

(1 - x + x^{2})^{4}

4 a^{4} - 25 a^{2} \cdot b^{2} + 36 b^{4}

2 \frac{x ^{43}}{2}

What is 0t+2(5+x)-(8+x)*(z+x)^2 ?
The solution to 0t+2(5+x)-(8+x)*(z+x)^2 is 10+2x-8z^2-xz^2-16xz-2x^2z-8x^2-x^3