What is (x+2)^2-(x+4)^2 ?

The solution to (x+2)^2-(x+4)^2 is -4x-12

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simplify (x+2)^2-(x+4)^2

simplify

(x + 2)^{2} - (x + 4)^{2}

- 4 x - 12

Solution steps

(x + 2)^{2} - (x + 4)^{2}

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

= x^{2} + 4 x + 4 - (x + 4)^{2}

Expand

- (x + 4)^{2} : - x^{2} - 8 x - 16

= x^{2} + 4 x + 4 - x^{2} - 8 x - 16

Group like terms

= x^{2} - x^{2} + 4 x - 8 x + 4 - 16

Add similar elements:

x^{2} - x^{2} = 0

= 4 x - 8 x + 4 - 16

Add similar elements:

4 x - 8 x = - 4 x

= - 4 x + 4 - 16

Subtract the numbers:

4 - 16 = - 12

= - 4 x - 12

(3 x^{2} - y^{2}) 2

\frac{( y ^{2} + 2 x y )}{x ^{2}}

[2 x^{2} + 4 x - 3] + [8 x^{2} + 2 x - 5]

5 x^{2} y - 2 x y^{2}

\frac{13}{2} x - \frac{5}{x}