What is (((1a))/4-((1b))/2+((1))/3)^2 ?

The solution to (((1a))/4-((1b))/2+((1))/3)^2 is ((3a-6b+4)^2)/(144)

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simplify (((1a))/4-((1b))/2+((1))/3)^2

simplify

(\frac{( 1 a )}{4} - \frac{( 1 b )}{2} + \frac{( 1 )}{3})^{2}

\frac{( 3 a - 6 b + 4 ) ^{2}}{144}

Solution steps

(\frac{1 \cdot a}{4} - \frac{1 \cdot b}{2} + \frac{1}{3})^{2}

Simplify

\frac{1 \cdot a}{4} - \frac{1 \cdot b}{2} + \frac{1}{3} : \frac{3 a - 6 b + 4}{12}

= (\frac{3 a - 6 b + 4}{12})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 a - 6 b + 4 ) ^{2}}{1 2 ^{2}}

1 2^{2} = 144

= \frac{( 3 a - 6 b + 4 ) ^{2}}{144}

\frac{a ^{2} + 1}{( 2 + 3 )}

\frac{lo g _{10} ( n ^{3} )}{lo g _{10} ( n )}

3 b - 2 b + b

3 a + 5 b - 7 a + 11 b + 8 a - 14 b

(2 y + 1)^{3}

What is (((1a))/4-((1b))/2+((1))/3)^2 ?
The solution to (((1a))/4-((1b))/2+((1))/3)^2 is ((3a-6b+4)^2)/(144)