What is ((((x^2+3))/4)^2-(x^3+x))/(2) ?

The solution to ((((x^2+3))/4)^2-(x^3+x))/(2) is (x^4+6x^2+9-16x^3-16x)/(32)

Popular >

simplify ((((x^2+3))/4)^2-(x^3+x))/(2)

simplify

\frac{( \frac{( x ^{2} + 3 )}{4} ) ^{2} - ( x ^{3} + x )}{2}

\frac{x ^{4} + 6 x ^{2} + 9 - 16 x ^{3} - 16 x}{32}

Solution steps

\frac{( \frac{x ^{2} + 3}{4} ) ^{2} - ( x ^{3} + x )}{2}

Simplify

(\frac{x ^{2} + 3}{4})^{2} - (x^{3} + x) : \frac{x ^{4} + 6 x ^{2} + 9 - 16 x ^{3} - 16 x}{16}

= \frac{\frac{x ^{4} + 6 x ^{2} + 9 - 16 x ^{3} - 16 x}{16}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ^{4} + 6 x ^{2} + 9 - 16 x ^{3} - 16 x}{16 \cdot 2}

Multiply the numbers:

16 \cdot 2 = 32

= \frac{x ^{4} + 6 x ^{2} + 9 - 16 x ^{3} - 16 x}{32}

- \frac{7}{8} \cdot a^{2} \cdot b^{5} \cdot \frac{c ^{8}}{( - \frac{5}{2} )} \cdot a \cdot b^{5} \cdot c^{6}

8 y + y

2 \frac{a}{b ^{- 1}} + 5 \frac{b}{a ^{- 1}}

3 x^{3} - 14 x

2 a^{3} + 10 a^{2} - 28 a

What is ((((x^2+3))/4)^2-(x^3+x))/(2) ?
The solution to ((((x^2+3))/4)^2-(x^3+x))/(2) is (x^4+6x^2+9-16x^3-16x)/(32)