What is (3a^2*b^{-3})^3*x*(2a^4)^{-3} ?

The solution to (3a^2*b^{-3})^3*x*(2a^4)^{-3} is (27x)/(8b^9a^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3a^2b^{-3})^3x*(2a^4)^{-3}

simplify

(3 a^{2} \cdot b^{- 3})^{3} \cdot x \cdot (2 a^{4})^{- 3}

\frac{27 x}{8 b ^{9} a ^{6}}

Solution steps

(3 a^{2} b^{- 3})^{3} x (2 a^{4})^{- 3}

Simplify

(3 a^{2} b^{- 3})^{3} : \frac{27 a ^{6}}{b ^{9}}

= \frac{27 a ^{6}}{b ^{9}} x (2 a^{4})^{- 3}

Simplify

(2 a^{4})^{- 3} : \frac{1}{8 a ^{12}}

= \frac{27 a ^{6}}{b ^{9}} x \frac{1}{8 a ^{12}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{27 a ^{6} x \cdot 1}{b ^{9} \cdot 8 a ^{12}}

Multiply the numbers:

27 \cdot 1 = 27

= \frac{27 a ^{6} x}{b ^{9} \cdot 8 a ^{12}}

Simplify

\frac{a ^{6}}{a ^{12}} : \frac{1}{a ^{6}}

= \frac{27 x}{b ^{9} \cdot 8 a ^{6}}

= \frac{27 x}{8 b ^{9} a ^{6}}

(- 0.5 z + 0.5) (- 4)

(3 q + 2 p)^{3}

7 x + 7 b

l^{- 1} \cdot {\frac{1}{( s ^{2} + a ^{2} )}}

1000000 x 1.0 8^{100}

What is (3a^2*b^{-3})^3*x*(2a^4)^{-3} ?
The solution to (3a^2*b^{-3})^3*x*(2a^4)^{-3} is (27x)/(8b^9a^6)