What is (x^2-3x)/(2-7) ?

The solution to (x^2-3x)/(2-7) is -(x^2-3x)/5

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simplify (x^2-3x)/(2-7)

simplify

\frac{x ^{2} - 3 x}{2 - 7}

- \frac{x ^{2} - 3 x}{5}

Solution steps

\frac{x ^{2} - 3 x}{2 - 7}

Subtract the numbers:

2 - 7 = - 5

= \frac{x ^{2} - 3 x}{- 5}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{x ^{2} - 3 x}{5}

5^{y} + 5^{y + 1}

(a^{- 1} + b^{- 1}) (a + b)^{- 1}

\frac{4.5 x 1 0 ^{- 2}}{8.3 x 1 0 ^{4}}

(x + a) (x - a) (x^{2} + a^{2}) (x^{4} + a^{4}) + a^{8}

det (b^{- 1} a^{- 1})