What is expand (b^{x+1}-3)(b^{x+1}-1) ?

The solution to expand (b^{x+1}-3)(b^{x+1}-1) is b^{2(x+1)}-4b^{x+1}+3

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expand (b^{x+1}-3)(b^{x+1}-1)

expand

(b^{x + 1} - 3) (b^{x + 1} - 1)

b^{2 (x + 1)} - 4 b^{x + 1} + 3

Solution steps

(b^{x + 1} - 3) (b^{x + 1} - 1)

Apply FOIL method

(b^{x + 1} - 3) (b^{x + 1} - 1) : b^{2 (x + 1)} - 4 b^{x + 1} + 3

= b^{2 (x + 1)} - 4 b^{x + 1} + 3

n + 1 + (- 2) n

∣ f (x) ∣^{2} - ∣ g (x) ∣^{2}

(\frac{( n - 1 )}{n})^{n}

6 x^{2} \cdot y - 4 x \cdot y^{2} + 10 x y

2 x^{2} - 4 x + 6 + 4 x^{2} + 5 x - 7

What is expand (b^{x+1}-3)(b^{x+1}-1) ?
The solution to expand (b^{x+1}-3)(b^{x+1}-1) is b^{2(x+1)}-4b^{x+1}+3