What is factor tan^2(t)-16cos^2(t) ?

The solution to factor tan^2(t)-16cos^2(t) is (tan(t)+4cos(t))(tan(t)-4cos(t))

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factor tan^2(t)-16cos^2(t)

factor

tan^{2} (t) - 16 cos^{2} (t)

(tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

Solution steps

tan^{2} (t) - 16 cos^{2} (t)

Simplify

16 cos^{2} (t) : (4 cos (t))^{2}

= tan^{2} (t) - (4 cos (t))^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

tan^{2} (t) - (4 cos (t))^{2} = (tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

= (tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

(\frac{x}{( x - 1 )})^{2} - 3 (\frac{x}{( x - 1 )}) - 18

\frac{( 2 ^{x} ) ^{x} - ( 2 ^{2} \cdot 2 ^{x} )}{2}

128 a^{3} - 250 b^{3}

\frac{arctan ( a )}{b - arctan ( a - \frac{b}{a} + b )}

148231 - 26115064461 - 50 a^{0}

What is factor tan^2(t)-16cos^2(t) ?
The solution to factor tan^2(t)-16cos^2(t) is (tan(t)+4cos(t))(tan(t)-4cos(t))