What is [(x^2-5)(x^2+5)]^2x^0 ?

The solution to [(x^2-5)(x^2+5)]^2x^0 is ((x^2-5)(x^2+5))^2

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simplify [(x^2-5)(x^2+5)]^2x^0

simplify

[(x^{2} - 5) (x^{2} + 5)]^{2} x^{0}

((x^{2} - 5) (x^{2} + 5))^{2}

Solution steps

((x^{2} - 5) (x^{2} + 5))^{2} x^{0}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= ((x^{2} - 5) (x^{2} + 5))^{2} \cdot 1

Apply rule:

a \cdot 1 = a

= ((x^{2} - 5) (x^{2} + 5))^{2}

(lo g_{10} (a^{b}))^{2}

f - 0.5 f

0.4 x^{3} - 0.9 x

x^{12} - y^{18}

\frac{( 4 x + 4 )}{2}

What is [(x^2-5)(x^2+5)]^2x^0 ?
The solution to [(x^2-5)(x^2+5)]^2x^0 is ((x^2-5)(x^2+5))^2