What is expand 3a(3a+2c)-4b(b+c) ?

The solution to expand 3a(3a+2c)-4b(b+c) is 9a^2+6ac-4b^2-4cb

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expand 3a(3a+2c)-4b(b+c)

expand

3 a (3 a + 2 c) - 4 b (b + c)

9 a^{2} + 6 a c - 4 b^{2} - 4 c b

Solution steps

3 a (3 a + 2 c) - 4 b (b + c)

Expand

3 a (3 a + 2 c) : 9 a^{2} + 6 a c

= 9 a^{2} + 6 a c - 4 b (b + c)

Expand

- 4 b (b + c) : - 4 b^{2} - 4 c b

= 9 a^{2} + 6 a c - 4 b^{2} - 4 c b

- 4 an - 1 - 3 an - 2 + 10 n^{2} - 2 n + 3

\frac{( ( 1 - 3 x ) ( 4 - x ) )}{( x )}

tan^{3} (x) + tan (x)

\frac{b ^{6}}{b ^{9}}

1 - cos^{2} (o)

What is expand 3a(3a+2c)-4b(b+c) ?
The solution to expand 3a(3a+2c)-4b(b+c) is 9a^2+6ac-4b^2-4cb