What is ((a^2b^2)-1)/((a-2a^1)^2) ?

The solution to ((a^2b^2)-1)/((a-2a^1)^2) is (a^2b^2-1)/(a^2)

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simplify ((a^2b^2)-1)/((a-2a^1)^2)

simplify

\frac{( a ^{2} b ^{2} ) - 1}{( a - 2 a ^{1} ) ^{2}}

\frac{a ^{2} b ^{2} - 1}{a ^{2}}

Solution steps

\frac{( a ^{2} b ^{2} ) - 1}{( a - 2 a ^{1} ) ^{2}}

Apply rule:

(a) = a

(a^{2} b^{2}) = a^{2} b^{2}

= \frac{a ^{2} b ^{2} - 1}{( a - 2 a ^{1} ) ^{2}}

Simplify

(a - 2 a^{1})^{2} : a^{2}

= \frac{a ^{2} b ^{2} - 1}{a ^{2}}

\frac{\frac{6}{x}}{y}

\frac{2}{x ^{2}} - \frac{5}{x} + 2

(\frac{- 4 m ^{2}}{n})^{3}

(\frac{2 x + 1}{( 2 x )})^{3}

n^{4} + n^{2} + 1

What is ((a^2b^2)-1)/((a-2a^1)^2) ?
The solution to ((a^2b^2)-1)/((a-2a^1)^2) is (a^2b^2-1)/(a^2)