What is expand log_{10}(y)(y-1) ?

The solution to expand log_{10}(y)(y-1) is ylog_{10}(y)-log_{10}(y)

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expand log_{10}(y)(y-1)

expand

lo g_{10} (y) (y - 1)

y lo g_{10} (y) - lo g_{10} (y)

Solution steps

lo g_{10} (y) (y - 1)

Apply the distributive law:

a (b - c) = ab - a c

lo g_{10} (y) (y - 1) = lo g_{10} (y) y - lo g_{10} (y) \cdot 1

= lo g_{10} (y) y - lo g_{10} (y) \cdot 1

Simplify

lo g_{10} (y) y - lo g_{10} (y) \cdot 1 : y lo g_{10} (y) - lo g_{10} (y)

= y lo g_{10} (y) - lo g_{10} (y)

9 a^{4} - x^{4}

\frac{sin ^{2} ( 2 x )}{sin ^{2} ( x )}

x (x^{\frac{1}{2}} - x)^{- 2}

a^{4} b^{4} - 16

(5 + x) 2

What is expand log_{10}(y)(y-1) ?
The solution to expand log_{10}(y)(y-1) is ylog_{10}(y)-log_{10}(y)