What is factor 100x^4-140x^2y^2+49y^4 ?

The solution to factor 100x^4-140x^2y^2+49y^4 is (10x^2-7y^2)^2

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factor 100x^4-140x^2y^2+49y^4

factor

100 x^{4} - 140 x^{2} y^{2} + 49 y^{4}

(10 x^{2} - 7 y^{2})^{2}

Solution steps

100 x^{4} - 140 x^{2} y^{2} + 49 y^{4}

Break the expression into groups

= (100 x^{4} - 70 x^{2} y^{2}) + (- 70 x^{2} y^{2} + 49 y^{4})

Factor out

10 x^{2}

from

100 x^{4} - 70 x^{2} y^{2} : 10 x^{2} (10 x^{2} - 7 y^{2})

Factor out

- 7 y^{2}

from

- 70 x^{2} y^{2} + 49 y^{4} : - 7 y^{2} (10 x^{2} - 7 y^{2})

= 10 x^{2} (10 x^{2} - 7 y^{2}) - 7 y^{2} (10 x^{2} - 7 y^{2})

Factor out common term

10 x^{2} - 7 y^{2}

= (10 x^{2} - 7 y^{2}) (10 x^{2} - 7 y^{2})

Apply exponent rule:

aa = a^{2}

(10 x^{2} - 7 y^{2}) (10 x^{2} - 7 y^{2}) = (10 x^{2} - 7 y^{2})^{2}

= (10 x^{2} - 7 y^{2})^{2}

\frac{8}{27} x^{3} - \frac{28}{3} x^{2} + 98 x - 343

4 x^{2} + 12 x - x - 3

4 a^{2} - 4 x^{2}

\frac{2 ( t - 8 ) ( t + 12 )}{2 t + 4}

(3 + 3 i) + 2 i

What is factor 100x^4-140x^2y^2+49y^4 ?
The solution to factor 100x^4-140x^2y^2+49y^4 is (10x^2-7y^2)^2