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Popular >

simplify 2^{1+log_{2}(n)}

Solution

simplify

2^{1 + l o g_{2} (n)}

Solution

2 n

Solution steps

2^{1 + l o g_{2} (n)}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{1 + l o g_{2} (n)} = 2 \cdot 2^{l o g_{2} (n)}

= 2 \cdot 2^{l o g_{2} (n)}

Apply log rule:

a^{l o g_{a} (b)} = b

2^{l o g_{2} (n)} = n

= 2 n

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Frequently Asked Questions (FAQ)

What is 2^{1+log_{2}(n)} ?
The solution to 2^{1+log_{2}(n)} is 2n