What is factor 64m^6-n^6 ?

The solution to factor 64m^6-n^6 is (2m+n)(4m^2-2mn+n^2)(2m-n)(4m^2+2mn+n^2)

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factor 64m^6-n^6

factor

64 m^{6} - n^{6}

(2 m + n) (4 m^{2} - 2 mn + n^{2}) (2 m - n) (4 m^{2} + 2 mn + n^{2})

Solution steps

64 m^{6} - n^{6}

64 m^{6} = (8 m^{3})^{2}

n^{6} = (n^{3})^{2}

= (8 m^{3})^{2} - (n^{3})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(8 m^{3})^{2} - (n^{3})^{2} = (8 m^{3} + n^{3}) (8 m^{3} - n^{3})

= (8 m^{3} + n^{3}) (8 m^{3} - n^{3})

Factor

8 m^{3} + n^{3} : (2 m + n) (4 m^{2} - 2 mn + n^{2})

= (2 m + n) (4 m^{2} - 2 mn + n^{2}) (8 m^{3} - n^{3})

Factor

8 m^{3} - n^{3} : (2 m - n) (4 m^{2} + 2 mn + n^{2})

= (2 m + n) (4 m^{2} - 2 mn + n^{2}) (2 m - n) (4 m^{2} + 2 mn + n^{2})

i \cdot 7 \cdot x^{2} - 12 x - 47

l x \frac{w}{2}

(8 x - 4 y)^{3}

\frac{2}{5} x - 1 \frac{x}{2}

3 (2 x - 2) + 8

What is factor 64m^6-n^6 ?
The solution to factor 64m^6-n^6 is (2m+n)(4m^2-2mn+n^2)(2m-n)(4m^2+2mn+n^2)