What are the solutions to the equation m^2+18m=-9 ?

The solutions to the equation m^2+18m=-9 are m=3(2sqrt(2)-3),m=-3(3+2sqrt(2))

Find the zeros of m^2+18m=-9

The zeros of m^2+18m=-9 are m=3(2sqrt(2)-3),m=-3(3+2sqrt(2))

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m^{2} + 18 m = - 9

m = 3 (22 - 3), m = - 3 (3 + 22)

Decimal Notation

m = - 0.51471 \dots, m = - 17.48528 \dots

Solution steps

m^{2} + 18 m = - 9

Move

9

to the left side

m^{2} + 18 m + 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 9 = 122

m_{1, 2} = \frac{- 18 \pm 12 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 18 + 12 2}{2 \cdot 1}, m_{2} = \frac{- 18 - 12 2}{2 \cdot 1}

m = \frac{- 18 + 12 2}{2 \cdot 1} : 3 (22 - 3)

m = \frac{- 18 - 12 2}{2 \cdot 1} : - 3 (3 + 22)

The solutions to the quadratic equation are:

m = 3 (22 - 3), m = - 3 (3 + 22)

0 \geq \frac{1}{2} x - 4 > 6

27 \cdot \frac{1}{3}

9 x^{3} - 9 x^{2} - 4 x + 4

3 x^{2} = 36

\frac{cos ( x )}{sin ( x )}

What are the solutions to the equation m^2+18m=-9 ?
The solutions to the equation m^2+18m=-9 are m=3(2sqrt(2)-3),m=-3(3+2sqrt(2))
Find the zeros of m^2+18m=-9
The zeros of m^2+18m=-9 are m=3(2sqrt(2)-3),m=-3(3+2sqrt(2))