What is 1/((xy)^{4/3)}(y(y+2x+1)) ?

The solution to 1/((xy)^{4/3)}(y(y+2x+1)) is (y+2x+1)/(x^{4/3)y^{1/3}}

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simplify 1/((xy)^{4/3)}(y(y+2x+1))

simplify

\frac{1}{( x y ) ^{\frac{4}{3}}} (y (y + 2 x + 1))

\frac{y + 2 x + 1}{x ^{\frac{4}{3}} y ^{\frac{1}{3}}}

Solution steps

\frac{1}{( x y ) ^{\frac{4}{3}}} (y (y + 2 x + 1))

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(x y)^{\frac{4}{3}} = x^{\frac{4}{3}} y^{\frac{4}{3}}

= \frac{1}{x ^{\frac{4}{3}} y ^{\frac{4}{3}}} y (y + 2 x + 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot y ( y + 2 x + 1 )}{x ^{\frac{4}{3}} y ^{\frac{4}{3}}}

Apply rule:

1 \cdot a = a

1 \cdot y (y + 2 x + 1) = y (y + 2 x + 1)

= \frac{y ( y + 2 x + 1 )}{x ^{\frac{4}{3}} y ^{\frac{4}{3}}}

Simplify

\frac{y}{y ^{\frac{4}{3}}} : \frac{1}{y ^{\frac{1}{3}}}

= \frac{y + 2 x + 1}{x ^{\frac{4}{3}} y ^{\frac{1}{3}}}

[(1000000000 a^{9})^{- \frac{1}{3}}]^{- \frac{1}{3}}

\frac{2 x + 2}{11} = \frac{x - 4}{6}

∣ b + 2 ∣ \leq 3

sin^{2} (x) - cos^{2} (x)

(- 2 k^{3} - 7 k^{2} + 5 k) + (6 k^{2} + 3 k)

What is 1/((xy)^{4/3)}(y(y+2x+1)) ?
The solution to 1/((xy)^{4/3)}(y(y+2x+1)) is (y+2x+1)/(x^{4/3)y^{1/3}}