What is (9x^3*y*10x^3+8x^2-5)-(7+10x^3-4x^3*y) ?

The solution to (9x^3*y*10x^3+8x^2-5)-(7+10x^3-4x^3*y) is 90x^6y+8x^2-12-10x^3+4x^3y

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simplify (9x^3y10x^3+8x^2-5)-(7+10x^3-4x^3*y)

simplify

(9 x^{3} \cdot y \cdot 10 x^{3} + 8 x^{2} - 5) - (7 + 10 x^{3} - 4 x^{3} \cdot y)

90 x^{6} y + 8 x^{2} - 12 - 10 x^{3} + 4 x^{3} y

Solution steps

(9 x^{3} y \cdot 10 x^{3} + 8 x^{2} - 5) - (7 + 10 x^{3} - 4 x^{3} y)

Apply rule:

(a) = a

(9 x^{3} y \cdot 10 x^{3} + 8 x^{2} - 5) = 9 x^{3} y \cdot 10 x^{3} + 8 x^{2} - 5

= 9 x^{3} y \cdot 10 x^{3} + 8 x^{2} - 5 - (7 + 10 x^{3} - 4 x^{3} y)

9 x^{3} y \cdot 10 x^{3} = 90 x^{6} y

- (7 + 10 x^{3} - 4 x^{3} y) = - 7 - 10 x^{3} + 4 x^{3} y

= 90 x^{6} y + 8 x^{2} - 5 - 7 - 10 x^{3} + 4 x^{3} y

Subtract the numbers:

- 5 - 7 = - 12

= 90 x^{6} y + 8 x^{2} - 12 - 10 x^{3} + 4 x^{3} y

(2 a^{2} b^{3}) (- 3 a^{- 4} b^{12})^{0}

c - \frac{b ^{2}}{4} a

d - \frac{\frac{4}{5}}{( - 3 )}

(2 x^{3} y)^{0}

(2) x^{2} + 2 3 x - 24

What is (9x^3*y*10x^3+8x^2-5)-(7+10x^3-4x^3*y) ?
The solution to (9x^3*y*10x^3+8x^2-5)-(7+10x^3-4x^3*y) is 90x^6y+8x^2-12-10x^3+4x^3y