What is factor 9a^4-34a^2*b^2+25b^4 ?

The solution to factor 9a^4-34a^2*b^2+25b^4 is (a+b)(a-b)(3a+5b)(3a-5b)

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factor 9a^4-34a^2*b^2+25b^4

factor

9 a^{4} - 34 a^{2} \cdot b^{2} + 25 b^{4}

(a + b) (a - b) (3 a + 5 b) (3 a - 5 b)

Solution steps

9 a^{4} - 34 a^{2} b^{2} + 25 b^{4}

Break the expression into groups

= (9 a^{4} - 9 a^{2} b^{2}) + (- 25 a^{2} b^{2} + 25 b^{4})

Factor out

9 a^{2}

from

9 a^{4} - 9 a^{2} b^{2} : 9 a^{2} (a^{2} - b^{2})

Factor out

- 25 b^{2}

from

- 25 a^{2} b^{2} + 25 b^{4} : - 25 b^{2} (a^{2} - b^{2})

= 9 a^{2} (a^{2} - b^{2}) - 25 b^{2} (a^{2} - b^{2})

Factor out common term

a^{2} - b^{2}

= (a^{2} - b^{2}) (9 a^{2} - 25 b^{2})

Factor

a^{2} - b^{2} : (a + b) (a - b)

= (a + b) (a - b) (9 a^{2} - 25 b^{2})

Factor

9 a^{2} - 25 b^{2} : (3 a + 5 b) (3 a - 5 b)

= (a + b) (a - b) (3 a + 5 b) (3 a - 5 b)

\frac{( x ^{2} - 7 x + 6 )}{( x - 6 )}

q^{2} r^{2} q^{4} r^{5}

(\frac{1}{( 4 3 )})^{n}

\frac{( 3 x ^{3} + 2 x ^{2} + 9 x + 6 )}{( x ^{2} + 3 )}

8383 s - 82 c 11 a

What is factor 9a^4-34a^2*b^2+25b^4 ?
The solution to factor 9a^4-34a^2*b^2+25b^4 is (a+b)(a-b)(3a+5b)(3a-5b)