What is factor 6x^3+7x^2-9x+2 ?

The solution to factor 6x^3+7x^2-9x+2 is (2x-1)(3x-1)(x+2)

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factor 6x^3+7x^2-9x+2

factor

6 x^{3} + 7 x^{2} - 9 x + 2

(2 x - 1) (3 x - 1) (x + 2)

Solution steps

6 x^{3} + 7 x^{2} - 9 x + 2

Use the rational root theorem

= (2 x - 1) \frac{6 x ^{3} + 7 x ^{2} - 9 x + 2}{2 x - 1}

\frac{6 x ^{3} + 7 x ^{2} - 9 x + 2}{2 x - 1} = 3 x^{2} + 5 x - 2

= (2 x - 1) (3 x^{2} + 5 x - 2)

Factor

3 x^{2} + 5 x - 2 : (3 x - 1) (x + 2)

= (2 x - 1) (3 x - 1) (x + 2)

\frac{7}{( 2 x )} - \frac{4}{( 5 x )} + \frac{5}{( x + 1 )}

\frac{x ^{2} - 1799 x}{30 - 2}

(2 x - 5 y)^{3} + (2 x + 5 y)^{3}

m^{3} + 9 n^{3} + (m + n)^{3}

\frac{( 2 x \cdot y ^{2} ) ^{5}}{( ( 4 x ^{2} \cdot y ) ^{2} ) \cdot ( x \cdot y ^{3} )}

What is factor 6x^3+7x^2-9x+2 ?
The solution to factor 6x^3+7x^2-9x+2 is (2x-1)(3x-1)(x+2)