What is l^{-1}*[((s-2))/(((s-2)^7))] ?

The solution to l^{-1}*[((s-2))/(((s-2)^7))] is 1/(l(s-2)^6)

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simplify l^{-1}*[((s-2))/(((s-2)^7))]

simplify

l^{- 1} \cdot \frac{( s - 2 )}{( ( s - 2 ) ^{7} )}

\frac{1}{l ( s - 2 ) ^{6}}

Solution steps

l^{- 1} (\frac{s - 2}{( s - 2 ) ^{7}})

Apply rule:

(a) = a

(\frac{s - 2}{( s - 2 ) ^{7}}) = \frac{s - 2}{( s - 2 ) ^{7}}

= l^{- 1} \frac{s - 2}{( s - 2 ) ^{7}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

l^{- 1} = \frac{1}{l}

= \frac{1}{l} \cdot \frac{s - 2}{( s - 2 ) ^{7}}

Cancel

\frac{s - 2}{( s - 2 ) ^{7}} : \frac{1}{( s - 2 ) ^{6}}

= \frac{1}{l} \cdot \frac{1}{( s - 2 ) ^{6}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{l ( s - 2 ) ^{6}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{l ( s - 2 ) ^{6}}

\frac{1}{2 x ( 7.9 + 4.8 ) \cdot x ^{5.2}}

(b + 8 c)^{3}

2 x^{3} - 11 x^{2} + 13 x - 4

\frac{3 x ^{3} + 3}{3}

(\frac{- b}{6})^{2}

What is l^{-1}*[((s-2))/(((s-2)^7))] ?
The solution to l^{-1}*[((s-2))/(((s-2)^7))] is 1/(l(s-2)^6)