What is factor a^{n+2}-a^{n-1} ?

The solution to factor a^{n+2}-a^{n-1} is a^{n-1}(a-1)(a^2+a+1)

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factor a^{n+2}-a^{n-1}

factor

a^{n + 2} - a^{n - 1}

a^{n - 1} (a - 1) (a^{2} + a + 1)

Solution steps

a^{n + 2} - a^{n - 1}

Factor out common term

a^{n - 1} : a^{n - 1} (a^{3} - 1)

= a^{n - 1} (a^{3} - 1)

Factor

a^{3} - 1 : (a - 1) (a^{2} + a + 1)

= a^{n - 1} (a - 1) (a^{2} + a + 1)

4 x^{5} - 9 x^{3} y^{2}

(- 2 w^{6} \cdot x^{- 5})^{2}

\frac{( a ) 71}{2 + ( - \frac{33}{5} )}

9 x^{2} + 6 z

\frac{( a ^{2} )}{( a ^{- 1} )}

What is factor a^{n+2}-a^{n-1} ?
The solution to factor a^{n+2}-a^{n-1} is a^{n-1}(a-1)(a^2+a+1)