What is (3i+5)-(2-4i) ?

The solution to (3i+5)-(2-4i) is 3+7i

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simplify (3i+5)-(2-4i)

simplify

(3 i + 5) - (2 - 4 i)

3 + 7 i

Solution steps

(3 i + 5) - (2 - 4 i)

Rewrite

3 i + 5

in standard complex form:

5 + 3 i

= 5 + 3 i - (2 - 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (5 - 2) + (3 - (- 4)) i

Simplify

(5 - 2) + (3 - (- 4)) i : 3 + 7 i

= 3 + 7 i

(\frac{65.4}{2}) \cdot x^{9.65} x^{1} x^{60} x^{6096500}

\frac{a}{b} + \frac{b}{a} + \frac{b}{c} + \frac{c}{b} + \frac{a}{c} + \frac{c}{a} + 3

m^{2} + \frac{1}{m ^{2}} + 2 - 2 m - \frac{2}{m}

21 b + 63 b^{2}

(x - 3)^{3} + y^{3}