What is (x-2)(x^2-2x+4)(x^2+2x+4)(x+2)+64 ?

The solution to (x-2)(x^2-2x+4)(x^2+2x+4)(x+2)+64 is x^6

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simplify (x-2)(x^2-2x+4)(x^2+2x+4)(x+2)+64

simplify

(x - 2) (x^{2} - 2 x + 4) (x^{2} + 2 x + 4) (x + 2) + 64

x^{6}

Solution steps

(x - 2) (x^{2} - 2 x + 4) (x^{2} + 2 x + 4) (x + 2) + 64

Expand

(x - 2) (x^{2} - 2 x + 4) (x^{2} + 2 x + 4) (x + 2) : x^{6} - 64

= x^{6} - 64 + 64

Add the numbers:

- 64 + 64 = 0

= x^{6}

(- 5 a^{3} b^{6})^{3}

\frac{3}{x} + 1 + \frac{5}{x} - 2

7 m^{2} n^{3} + 14 m^{3} n^{2} - 21 m^{3} n^{4}

6 (7 x - 4)^{2} + 4

\frac{( x - 1 ) ( - x + 1 ) ( x + 2 ) + 2 ( x - 1 ) - ( x )}{( x - 1 ) ^{2}}

What is (x-2)(x^2-2x+4)(x^2+2x+4)(x+2)+64 ?
The solution to (x-2)(x^2-2x+4)(x^2+2x+4)(x+2)+64 is x^6