What is ((2^k)^+)^1+((2^k)^+)^1-2 ?

The solution to ((2^k)^+)^1+((2^k)^+)^1-2 is 2^{1+k}-2

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simplify ((2^k)^+)^1+((2^k)^+)^1-2

simplify

((2^{k})^{+})^{1} + ((2^{k})^{+})^{1} - 2

2^{1 + k} - 2

Solution steps

((2^{k})^{+})^{1} + ((2^{k})^{+})^{1} - 2

Apply rule

a^{1} = a

((2^{k}))^{1} = (2^{k})

= (2^{k}) + (2^{k}) - 2

Add similar elements:

(2^{k}) + (2^{k}) = 2 (2^{k})

= 2 (2^{k}) - 2

2 (2^{k})^{+} = 2^{1 + k}

= 2^{k + 1} - 2

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What is ((2^k)^+)^1+((2^k)^+)^1-2 ?
The solution to ((2^k)^+)^1+((2^k)^+)^1-2 is 2^{1+k}-2