What is (f[(-1/3)^{-3}-(1/2)^{-2}])/(((1/4)^2)) ?

The solution to (f[(-1/3)^{-3}-(1/2)^{-2}])/(((1/4)^2)) is -496f

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simplify (f[(-1/3)^{-3}-(1/2)^{-2}])/(((1/4)^2))

simplify

\frac{f [ ( - \frac{1}{3} ) ^{- 3} - ( \frac{1}{2} ) ^{- 2} ]}{( ( \frac{1}{4} ) ^{2} )}

- 496 f

Solution steps

\frac{f ( ( - \frac{1}{3} ) ^{- 3} - ( \frac{1}{2} ) ^{- 2} )}{( \frac{1}{4} ) ^{2}}

Simplify

f ((- \frac{1}{3})^{- 3} - (\frac{1}{2})^{- 2}) : - f \cdot 31

= \frac{- f \cdot 31}{( \frac{1}{4} ) ^{2}}

(\frac{1}{4})^{2} = \frac{1}{16}

= \frac{- f \cdot 31}{\frac{1}{16}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{- f \cdot 31 \cdot 16}{1}

Cancel

\frac{- f \cdot 31 \cdot 16}{1} : - f \cdot 496

= - f \cdot 496

= - 496 f

\frac{3}{2} - \frac{x}{2}

\frac{t ^{- 3}}{2}

6 cos^{2} (- p)

cos (x) + cos^{3} (x)

729 y^{3} - 64

What is (f[(-1/3)^{-3}-(1/2)^{-2}])/(((1/4)^2)) ?
The solution to (f[(-1/3)^{-3}-(1/2)^{-2}])/(((1/4)^2)) is -496f