What is (2a^3)^2*(-2)^4*(a^2*b^2)^3 ?

The solution to (2a^3)^2*(-2)^4*(a^2*b^2)^3 is 64a^{12}b^6

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simplify (2a^3)^2(-2)^4(a^2*b^2)^3

simplify

(2 a^{3})^{2} \cdot (- 2)^{4} \cdot (a^{2} \cdot b^{2})^{3}

64 a^{12} b^{6}

Solution steps

(2 a^{3})^{2} (- 2)^{4} (a^{2} b^{2})^{3}

Simplify

(2 a^{3})^{2} : 4 a^{6}

= 4 a^{6} (- 2)^{4} (a^{2} b^{2})^{3}

(- 2)^{4} = 16

= 4 a^{6} \cdot 16 (a^{2} b^{2})^{3}

Simplify

(a^{2} b^{2})^{3} : a^{6} b^{6}

= 4 a^{6} \cdot 16 a^{6} b^{6}

Multiply the numbers:

4 \cdot 16 = 64

= 64 a^{6} a^{6} b^{6}

Simplify

a^{6} a^{6} : a^{12}

= 64 a^{12} b^{6}

a^{2} - b^{2} - a - b

\frac{( d - d ^{2} )}{( d ^{2} )}

(3 x 1 0^{8})^{2}

(\frac{2 x + 1}{3 y})^{3}

\frac{( 3 - 1 )}{( 3 + 1 ) - a - b \cdot 3}

What is (2a^3)^2*(-2)^4*(a^2*b^2)^3 ?
The solution to (2a^3)^2*(-2)^4*(a^2*b^2)^3 is 64a^{12}b^6