simplify (w^{-3})^5

Solution

simplify

(w^{- 3})^{5}

\frac{1}{w ^{15}}

Solution steps

(w^{- 3})^{5}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= w^{- 3 \cdot 5}

Multiply the numbers:

3 \cdot 5 = 15

= w^{- 15}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

w^{- 15} = \frac{1}{w ^{15}}

= \frac{1}{w ^{15}}

(- 5 - a) (- 5 - a)

\frac{( - 1 ) ^{x + 3}}{( - 1 ) ^{x + 2}}

\frac{a ^{2} + 1 - 6}{( a ^{2} )}

\frac{( y - x )}{( x ^{2} - y ^{2} )}

25 x^{2} - 9 a^{2}