What is 3(2x-1)(x+4)-(2x-1)^2 ?

The solution to 3(2x-1)(x+4)-(2x-1)^2 is 2x^2+25x-13

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simplify 3(2x-1)(x+4)-(2x-1)^2

simplify

3 (2 x - 1) (x + 4) - (2 x - 1)^{2}

2 x^{2} + 25 x - 13

Solution steps

3 (2 x - 1) (x + 4) - (2 x - 1)^{2}

Expand

3 (2 x - 1) (x + 4) : 6 x^{2} + 21 x - 12

= 6 x^{2} + 21 x - 12 - (2 x - 1)^{2}

Expand

- (2 x - 1)^{2} : - 4 x^{2} + 4 x - 1

= 6 x^{2} + 21 x - 12 - 4 x^{2} + 4 x - 1

Group like terms

= 6 x^{2} - 4 x^{2} + 21 x + 4 x - 12 - 1

Add similar elements:

6 x^{2} - 4 x^{2} = 2 x^{2}

= 2 x^{2} + 21 x + 4 x - 12 - 1

Add similar elements:

21 x + 4 x = 25 x

= 2 x^{2} + 25 x - 12 - 1

Subtract the numbers:

- 12 - 1 = - 13

= 2 x^{2} + 25 x - 13

sin (9 0^{\circ}) - a

\frac{{ ( x - \frac{1}{2} ) ^{2} - \frac{21}{4} }}{( x - 1 - \frac{2}{x} )}

\frac{- 9 - 3 x ( - 3 ) + [ - 3 + 11 x ( - 3 ) ]}{2}

12 x^{5} y^{3} - 4 x^{2} y^{2}

- 273.1 5^{0} c

What is 3(2x-1)(x+4)-(2x-1)^2 ?
The solution to 3(2x-1)(x+4)-(2x-1)^2 is 2x^2+25x-13