What is factor x^3+2x^2-6x+3 ?

The solution to factor x^3+2x^2-6x+3 is (x-1)(x^2+3x-3)

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factor x^3+2x^2-6x+3

factor

x^{3} + 2 x^{2} - 6 x + 3

(x - 1) (x^{2} + 3 x - 3)

Solution steps

x^{3} + 2 x^{2} - 6 x + 3

Use the rational root theorem

= (x - 1) \frac{x ^{3} + 2 x ^{2} - 6 x + 3}{x - 1}

\frac{x ^{3} + 2 x ^{2} - 6 x + 3}{x - 1} = x^{2} + 3 x - 3

= (x - 1) (x^{2} + 3 x - 3)

(- 5 x 1 0^{1})^{- 2}

\frac{x ^{2} + ( x + 1 )}{( x ^{3} ) + 2 x ( 2 )}

3 x^{2} + 6 x^{0.3} x^{2} - 6 x

4.52 \times 1 0^{- 1} 6/0.5 \times 25

(\frac{6}{5} - \frac{1}{3}) \cdot \frac{x ^{3}}{26}

What is factor x^3+2x^2-6x+3 ?
The solution to factor x^3+2x^2-6x+3 is (x-1)(x^2+3x-3)