What is (3x^3*y^{-2})^{-4} ?

The solution to (3x^3*y^{-2})^{-4} is (y^8)/(81x^{12)}

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simplify (3x^3*y^{-2})^{-4}

simplify

(3 x^{3} \cdot y^{- 2})^{- 4}

\frac{y ^{8}}{81 x ^{12}}

Solution steps

(3 x^{3} y^{- 2})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 x^{3} y^{- 2})^{- 4} = \frac{1}{( 3 x ^{3} y ^{- 2} ) ^{4}}

= \frac{1}{( 3 x ^{3} y ^{- 2} ) ^{4}}

Simplify

(3 x^{3} y^{- 2})^{4} : \frac{81 x ^{12}}{y ^{8}}

= \frac{1}{\frac{81 x ^{12}}{y ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{8}}{81 x ^{12}}

x^{4} + 4 x^{2} \cdot y^{2} + 16 y^{4}

(- 2 a^{3} b^{2})^{3}

(3 x + 2)^{2} - (3 x - 1)^{2} - 3 (2 x + 1)

(\frac{15}{10 t - 8}) 2

8 x^{2} - 10 x^{4} - 0.342 + 16 x + 114 - 10

What is (3x^3*y^{-2})^{-4} ?
The solution to (3x^3*y^{-2})^{-4} is (y^8)/(81x^{12)}