What is 4((x+2))/3+2((7x-3))/5 ?

The solution to 4((x+2))/3+2((7x-3))/5 is (4(x+2))/3+(2(7x-3))/5

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simplify 4((x+2))/3+2((7x-3))/5

simplify

4 \frac{( x + 2 )}{3} + 2 \frac{( 7 x - 3 )}{5}

\frac{4 ( x + 2 )}{3} + \frac{2 ( 7 x - 3 )}{5}

Solution steps

4 \cdot \frac{x + 2}{3} + 2 \cdot \frac{7 x - 3}{5}

4 \cdot \frac{x + 2}{3} = \frac{4 ( x + 2 )}{3}

2 \cdot \frac{7 x - 3}{5} = \frac{2 ( 7 x - 3 )}{5}

= \frac{4 ( x + 2 )}{3} + \frac{2 ( 7 x - 3 )}{5}

f (x) 2 x^{2} - 12 x - 10

- 0.05 (x - 3.5)^{2} + 0.8

e^{x} 1 + x + \frac{x ^{2}}{2} + \frac{x ^{3}}{3}

18 x^{2} + 6 b - 8

\frac{( 5 a - 15 b )}{( - 5 )}

What is 4((x+2))/3+2((7x-3))/5 ?
The solution to 4((x+2))/3+2((7x-3))/5 is (4(x+2))/3+(2(7x-3))/5