What is (3x^3)/(6y^2)*(4y^5)/(7x^4) ?

The solution to (3x^3)/(6y^2)*(4y^5)/(7x^4) is (2y^3)/(7x)

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simplify (3x^3)/(6y^2)*(4y^5)/(7x^4)

simplify

\frac{3 x ^{3}}{6 y ^{2}} \cdot \frac{4 y ^{5}}{7 x ^{4}}

\frac{2 y ^{3}}{7 x}

Solution steps

\frac{3 x ^{3}}{6 y ^{2}} \cdot \frac{4 y ^{5}}{7 x ^{4}}

Cancel

\frac{3 x ^{3}}{6 y ^{2}} : \frac{x ^{3}}{2 y ^{2}}

= \frac{x ^{3}}{2 y ^{2}} \cdot \frac{4 y ^{5}}{7 x ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{3} \cdot 4 y ^{5}}{2 y ^{2} \cdot 7 x ^{4}}

Factor the number:

4 = 2 \cdot 2

= \frac{x ^{3} \cdot 2 \cdot 2 y ^{5}}{2 y ^{2} \cdot 7 x ^{4}}

Cancel the common factor:

2

= \frac{x ^{3} \cdot 2 y ^{5}}{y ^{2} \cdot 7 x ^{4}}

Simplify

\frac{y ^{5}}{y ^{2}} : y^{3}

= \frac{x ^{3} \cdot 2 y ^{3}}{7 x ^{4}}

Simplify

\frac{x ^{3}}{x ^{4}} : \frac{1}{x}

= \frac{2 y ^{3}}{7 x}

∣ y ∣ - 3 \leq 0

(y^{2})^{4}

\frac{x - 3}{x + 1} < 1

r^{2} + 3 r - 1 = 0

2 x y - 2 x^{2} y^{2}

What is (3x^3)/(6y^2)*(4y^5)/(7x^4) ?
The solution to (3x^3)/(6y^2)*(4y^5)/(7x^4) is (2y^3)/(7x)