What is d(d-1)-4(d')-4d'-1 ?

The solution to d(d-1)-4(d')-4d'-1 is d^2-d-8d'-1

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simplify d(d-1)-4(d')-4d'-1

simplify

d (d - 1) - 4 (d^{'}) - 4 d^{'} - 1

d^{2} - d - 8 d' - 1

Solution steps

d (d - 1) - 4 (d^{'}) - 4 d^{'} - 1

Remove parentheses:

(a) = a

= d (d - 1) - 4 d^{^{'}} - 4 d^{^{'}} - 1

Expand

d (d - 1) : d^{2} - d

= d^{2} - d - 4 d^{'} - 4 d^{'} - 1

Add similar elements:

- 4 d^{'} - 4 d^{'} = - 8 d^{'}

= d^{2} - d - 8 d^{^{'}} - 1

1 7^{\frac{1}{2}} \cdot 1 7^{\frac{1}{2}}

x (- 2 x^{3} + 2 x - 2 x^{2} + 5)

\frac{( x ^{2} + 2 x + 1 )}{( x + 1 )}

sin (x) + sin^{3} (x)

16 x^{4} + 4 x^{2} y^{2} + y^{4}